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Last modified: September 20, 2019

Usually, when we think about the new features that came with version 8 of Java, functional programming and lambda expressions are first things that come to mind.

Nevertheless, besides those big features there're others, maybe having a smaller impact but also interesting and many times not really well known or even covered by any review.

In this tutorial, we'll enumerate and give a little example of each of the new methods added to one of the core classes of the language: *java.lang.Math*.

First, we have a group of new methods that extend some of the existing and most common arithmetic operations.

As we'll see, they're quite self-explanatory, as they have exactly the same functionality than the methods they derive from but with **the addition of throwing an exception in case, the resulting value overflows the max or min values of their types.**

We can use these methods with both *integers* and *longs* as parameters.

Adds the two parameters, **throwing an ArithmeticException in case of overflow (which goes for all *Exact() methods)** of the addition:

Math.addExact(100, 50); // returns 150 Math.addExact(Integer.MAX_VALUE, 1); // throws ArithmeticException

Substracts the value of the second parameter from the first one, throwing an *ArithmeticException* in case of overflow of the subtraction:

Math.subtractExact(100, 50); // returns 50 Math.subtractExact(Long.MIN_VALUE, 1); // throws ArithmeticException

Increments the parameter by one, throwing an *ArithmeticException* in case of overflow:

Math.incrementExact(100); // returns 101 Math.incrementExact(Integer.MAX_VALUE); // throws ArithmeticException

Decrements the parameter by one, throwing an *ArithmeticException* in case of overflow:

Math.decrementExact(100); // returns 99 Math.decrementExact(Long.MIN_VALUE); // throws ArithmeticException

Multiply the two parameters, throwing an *ArithmeticException* in case of overflow of the product:

Math.multiplyExact(100, 5); // returns 500 Math.multiplyExact(Long.MAX_VALUE, 2); // throws ArithmeticException

Changes the sign of the parameter, throwing an *ArithmeticException* in case of overflow.

In this case, we have to think about the internal representation of the value in memory to understand why there's an overflow, as is not as intuitive as the rest of the “exact” methods:

Math.negateExact(100); // returns -100 Math.negateExact(Integer.MIN_VALUE); // throws ArithmeticException

The second example requires an explanation as it's not obvious: **The overflow is due to the Integer.MIN_VALUE being −2.147.483.648, and on the other side the Integer.MAX_VALUE being 2.147.483.647** so the returned value doesn't fit into an

Divides the first parameter by the second one, and then performs a *floor()* operation over the result, returning the *Integer* that is less or equal to the quotient:

Math.floorDiv(7, 2)); // returns 3

The exact quotient is 3.5 so *floor(3.5)* == 3.

Let's look at another example:

Math.floorDiv(-7, 2)); // returns -4

The exact quotient is -3.5 so *floor(-3.5)* == -4.

This one is similar to the previous method *floorDiv()*, but applying the *floor()* operation over the modulus or remainder of the division instead of the quotient:

Math.modDiv(5, 3)); // returns 2

As we can see, the ** modDiv() for two positive numbers is the same as % operator**. Let's look at a different example:

Math.modDiv(-5, 3)); // returns 1

It returns 1 and not 2 because *floorDiv(-5, 3)* is -2 and not -1.

Returns the immediately lower value of the parameter (supports *float* or *double* parameters):

float f = Math.nextDown(3); // returns 2.9999998 double d = Math.nextDown(3); // returns 2.999999761581421

In this article, we've described briefly the functionality of all the new methods added to the class ** java.lang.Math** in the version 8 of the Java platform and also seen some examples of how to use them.

As always, the full source code is available over on GitHub.