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Last modified: January 20, 2020

In this tutorial, we first learn what minimum spanning trees are. Afterward, we'll use Prim's algorithm to find one.

**A minimum spanning tree (MST) is a weighted, undirected, connected graph whose total edge weight has been minimized by removing heavier edges**. In other words, we keep all the vertices of the graph intact, but we may remove some edges so that the sum of all edges is at a minimum.

We start with a weighted graph since it makes no sense to minimize the total edge weight if those edges have no weight at all. Let's take a look at an example graph:

The above graph is a weighted, undirected, connected graph. Here is an MST of that graph:

An MST of a graph is not unique, though. If a graph has more than one MST, then each MST has the same total edge weight.

**Prim's algorithm takes a weighted, undirected, connected graph as input and returns an MST of that graph as output**.

**It works in a greedy manner**. In the first step, it selects an arbitrary vertex. Thereafter, **each new step adds the nearest vertex to the tree constructed so far** until there is no disconnected vertex left.

Let's run Prim's algorithm on this graph step-by-step:

Assuming the arbitrary vertex to start the algorithm is B, we have three choices A, C, and E to go. The corresponding weights of the edges are 2, 2, and 5, therefore the minimum is 2. In this case, we have two edges weighing 2, so we can choose either of them (it doesn't matter which one). Let's choose A:

Now we have a tree with two vertices A and B. We can select any of A or B's edges not yet added that lead to an unadded vertex. So, we can pick AC, BC, or BE.

Prim's algorithm chooses the minimum, which is 2, or BC:

Now we have a tree with three vertices and three possible edges to move forward: CD, CE, or BE. AC isn't included since it wouldn't add a new vertex to the tree. The minimum weight amongst these three is 1.

However, there are two edges both weighing 1. Consequently, Prim's algorithm chooses one of them (again doesn't matter which one) in this step:

There is only one vertex left to join, so we can pick from CE and BE. The minimum weight that can connect our tree to it is 1, and Prim's algorithm will choose it:

As all vertices of the input graph are now present in the output tree, Prim's algorithm ends. Therefore, this tree is an MST of the input graph.

Vertices and edges make graphs, so we need a data structure to store these elements. Let's create the class *Edge*:

public class Edge { private int weight; private boolean isIncluded = false; }

Each *Edge* must have a *weight *since Prim's algorithm works on weighted graphs. *isIncluded* shows whether the *Edge* is present in the minimum spanning tree or not.

Now, let's add the *Vertex* class:

public class Vertex { private String label = null; private Map<Vertex, Edge> edges = new HashMap<>(); private boolean isVisited = false; }

Each *Vertex* can optionally have a *label*. We use the *edges* map to store connections among vertices. Finally, *isVisited* shows whether the vertex has been visited by Prim's algorithm so far or not.

Let's create our *Prim* class where we'll implement the logic:

public class Prim { private List<Vertex> graph; }

A list of vertices is enough to store the whole graph because inside each *Vertex*, we have a *Map<Vertex, Edge>* to identify all connections. Inside *Prim, *we create a *run() *method:

public void run() { if (graph.size() > 0) { graph.get(0).setVisited(true); } while (isDisconnected()) { Edge nextMinimum = new Edge(Integer.MAX_VALUE); Vertex nextVertex = graph.get(0); for (Vertex vertex : graph) { if (vertex.isVisited()) { Pair<Vertex, Edge> candidate = vertex.nextMinimum(); if (candidate.getValue().getWeight() < nextMinimum.getWeight()) { nextMinimum = candidate.getValue(); nextVertex = candidate.getKey(); } } } nextMinimum.setIncluded(true); nextVertex.setVisited(true); } }

We start by setting the first element of the *List<Vertex> graph* as visited. The first element can be any of the vertices depending on the order they've been added to the list in the first place. *isDisconnected()* returns *true* if there is any *Vertex* not visited so far:

private boolean isDisconnected() { for (Vertex vertex : graph) { if (!vertex.isVisited()) { return true; } } return false; }

While the minimum spanning tree *isDisconnected()*, we loop over the already visited vertices and find the *Edge* with the minimum weight as a candidate for *nextVertex:*

public Pair<Vertex, Edge> nextMinimum() { Edge nextMinimum = new Edge(Integer.MAX_VALUE); Vertex nextVertex = this; Iterator<Map.Entry<Vertex,Edge>> it = edges.entrySet() .iterator(); while (it.hasNext()) { Map.Entry<Vertex,Edge> pair = it.next(); if (!pair.getKey().isVisited()) { if (!pair.getValue().isIncluded()) { if (pair.getValue().getWeight() < nextMinimum.getWeight()) { nextMinimum = pair.getValue(); nextVertex = pair.getKey(); } } } } return new Pair<>(nextVertex, nextMinimum); }

We find the minimum of all *candidate*s in the main loop and store it in *nextVertex*. Then, we set *nextVertex* as visited. The loop goes on until all vertices are visited.

At the end,** each Edge with isIncluded equal to true is present.**

Note that since *nextMinimum()* iterates through the edges, the time complexity of this implementation is *O(V ^{2})*. If we store the edges in a priority queue (sorted by weight) instead, the algorithm will perform in

Okay, so now that we've got some code, let's test it with a real example. First, we construct our graph:

public static List<Vertex> createGraph() { List<Vertex> graph = new ArrayList<>(); Vertex a = new Vertex("A"); ... Vertex e = new Vertex("E"); Edge ab = new Edge(2); a.addEdge(b, ab); b.addEdge(a, ab); ... Edge ce = new Edge(1); c.addEdge(e, ce); e.addEdge(c, ce); graph.add(a); ... graph.add(e); return graph; }

The constructor of the *Prim* class takes it and stores it inside the class. We can print the input graph with *originalGraphToString()* method:

Prim prim = new Prim(createGraph()); System.out.println(prim.originalGraphToString());

Our example will output:

A --- 2 --- B A --- 3 --- C B --- 5 --- E B --- 2 --- C C --- 1 --- E C --- 1 --- D

Now, we run Prim's algorithm and print the resulting MST with *minimumSpanningTreeToString()* method:

prim.run(); prim.resetPrintHistory(); System.out.println(prim.minimumSpanningTreeToString());

Finally, we print out our MST:

A --- 2 --- B B --- 2 --- C C --- 1 --- E C --- 1 --- D

In this article, we learned how Prim's algorithm finds a minimum spanning tree of a graph. The code is available over on GitHub.