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1. Overview

Python, Perl, Tcl, and all UNIX shell scripting languages (like Bash) are examples of interpreted languages. This is the reason why Bash reads and interprets one command at a time and doesn’t segregate its variables by type. In fact, Bash is untyped.

In this tutorial, let’s go deeper and see how it’s possible to check if a variable is effectively a number. First, we’re going to show many possible solutions in detail. Second, we’ll explain the idea behind each solution.

2. Comparing Variables

Bash considers its variables as character strings, but it allows all arithmetical operations and comparisons on the variables. The basic idea is that to evaluate if a variable is a number, we need to verify that its value contains only digits.

2.1. Using Regular Expressions

As a first example, let’s write a script called integers.sh that uses a regular expression to make sure the given input is an integer value:

#!/bin/bash
echo $1 | grep "^-\?[0-9]+$"

The main ingredients are:

  • $1 contains the value of the parameter passed to the script invocation
  • a regular expression is here defined after the grep command

More precisely, the Unix pipe provides the standard output of the first process (echo command) to the standard input of the second command (grep command). The accepted characters are numbers between 0 and 9. In addition to that, the sign along with the dashes states that we can use negative numbers.

If we want to define the regular expression for the positive numbers, we simply need to remove the dash sign only. So, let’s show two examples of the invocation of the previous script. Using an integer value, we have:

$ ./integers.sh 123 
123

Otherwise, with a string, we get:

$ ./integers.sh cat

As we can see, the regular expression correctly accepts the integer value, and as expected, it rejects the word and doesn’t print it on the console.

2.2. Using the Equal Tilde Operator

Another way to solve the problem is using the Equal Tilde (=~) operator. This allows the use of the regular expressions in an if statement:

#!/bin/bash 
if ! [[ $1 =~ '^[0-9]+$' ]]; 
   then echo "error: Not a number" >&2; exit 1 
fi

The right side of the boolean condition is an extended regular expression. If the left side matches, the operator returns 0, and otherwise, it returns 1.

Let’s group these last instructions in a script called ext-regexp.sh and invoke it:

$ ./ext-regexp.sh 1
$ ./ext-regexp.sh a 
error: Not a number

This means that the script correctly ends with status 0 in case we use a number. Otherwise, it reports the error and exits with status 1.

2.3. Matching Real Numbers

We can simply change the matching rule for the regular expression to recognize the real numbers:

^[0-9]+([.][0-9]+)?$

For the real numbers with the sign, we need to use:

^[+-]?[0-9]+([.][0-9]+)?$

3. Conclusions

In this tutorial, we’ve explained how to check if a variable is a number in Bash. The proposed solutions all rely on the use of regular expressions.

Authors Bottom

If you have a few years of experience in the Linux ecosystem, and you’re interested in sharing that experience with the community, have a look at our Contribution Guidelines.

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